9x^(2/3)-62x^(1/3)-7=0

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Solution for 9x^(2/3)-62x^(1/3)-7=0 equation: 


x in (-oo:+oo)

9*x^(2/3)-(62*x^(1/3))-7 = 0

9*x^(2/3)-62*x^(1/3)-7 = 0

t_1 = x^(1/3)

9*t_1^2-62*t_1^1-7 = 0

9*t_1^2-62*t_1-7 = 0

DELTA = (-62)^2-(-7*4*9)

DELTA = 4096

DELTA > 0

t_1 = (4096^(1/2)+62)/(2*9) or t_1 = (62-4096^(1/2))/(2*9)

t_1 = 7 or t_1 = -1/9

t_1 = -1/9

x^(1/3)+1/9 = 0

1*x^(1/3) = -1/9 // : 1

x^(1/3) = -1/9

( -1/9 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 7

x^(1/3)-7 = 0

1*x^(1/3) = 7 // : 1

x^(1/3) = 7

x^(1/3) = 7 // ^ 3

x = 343

x = 343

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